You need to add 98,000 mls of water to the 14000 mls of 80% acid.
We are diluting an 80% aqueous acid solution down to a 10% aqueous acid solution
First lets get our numbers lined up
14, 000 mls of 80% acid solution contains
14,000*0.8 = 11,200 mls of acid
14,000*0.2 = 2,800 mls of water
11,200/0.1 = 112,000 mls of 10% aqueous solution
Since we already have 14,000 mls of the concentrated 80% acid we need to subtract that volume out to determine how much water is needed
112,000 - 14,000 = 98,000 mls of water is needed
Now to check our numbers we have
From our 14,000 ml of 80%
11,200 mls of acid
2,800 mls of water
From the addition
98,000 mls of water
Totals
100800 mls of water + 11,200 mls of acid = 112000 mls of 10% acid solution
(100800/112000)* 100 = 90% for the water
(11200/112000)* 100 = 10% for the acid
Checking
14000 + 98000 = 112000
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