
Al P. answered 07/08/19
Precalculus tutoring
cos(θ) = 1/2 --> θ = cos-1(1/2) = 60o
Now, we know cos(θ) = cos(-θ) so cos(-60o) = 1/2. However, a negative angle is a CW rotation, if we instead do the standard CCW rotation starting at 0o, we see -60o is the same angle as 300o.
That's two solutions. Both of these solutions are less than 360o, and require less than one rotation around the unit circle. You can get ⋅as many more solutions as you want by adding 360n degrees to each angle. Adding 360 degrees simply rotates around the unit circle exactly once, so 360n is exactly n rotations:
cos(60 + 360n) = 1/2 for n=0,1,2,3,,...
cos(300 + 360n) = 1/2 for n=0,1,2,3,,...
You can let n=0,1,2 in each of the above to get 6 specific solutions:
cos(60o) = cos(420o) = cos(780o) = 1/2
cos(300o) = cos(660o) = cos(1020o) = 1/2
I encourage you to plug in the above values on a calculator to see that they all have cosine of 1/2 (make sure your calculator is set to "degrees" mode). For this problem, you could also just let n=0,1,...,5 in, say, the first equation.