J.R. S. answered 07/08/19
Ph.D. University Professor with 10+ years Tutoring Experience
Assuming that you are referring to the same reaction as in your previous question, we have...
4HCl + O2 ==> 2H2O + 2Cl2
Moles of O2 used = 27.2 g O2 x 1 mol/32 g = 0.85 moles O2
Mass Cl2 produced = 0.85 moles O2 x 2 moles Cl2/1 mole O2 x 71.0 g Cl2/mole Cl2 = 121 g Cl2 (3 sig figs)