J.R. S. answered 07/06/19
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Ph.D. University Professor with 10+ years Tutoring Experience
(H3O+)(OH-) = 1x10-14
OH = 1x10-14/ H3O
plug in values of H3O and solve for OH-
Bailee N.
asked 07/06/19baking soda, 1.0×10−8 M
orange juice, 2.5×10−4 M
milk, 5.0×10−7 M
bleach, 6.0×10−12 M
J.R. S. answered 07/06/19
Ph.D. University Professor with 10+ years Tutoring Experience
(H3O+)(OH-) = 1x10-14
OH = 1x10-14/ H3O
plug in values of H3O and solve for OH-
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