J.R. S. answered 07/06/19
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Ph.D. University Professor with 10+ years Tutoring Experience
(H3O+)(OH-) = 1x10-14
H3O+ = 1x10-14/[OH-]
plug in the OH values and solve for H3O+
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J.R. S. answered 07/06/19
Ph.D. University Professor with 10+ years Tutoring Experience
(H3O+)(OH-) = 1x10-14
H3O+ = 1x10-14/[OH-]
plug in the OH values and solve for H3O+
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