Let:
l be the length of the side of the rectangle and
w be the width.
We know the length is three times the width:
l = 3w.
The perimeter is the sum of all sides of the rectangle
P = l + w + l + w
P = 3w + w + 3w + w
P = 8w.
We substitute P with 80 and solve for w:
80 = 8w
w = 10m.
We find the length:
l = 3w
l = 30m.
The area is
A = lw
A = 30x10
A =300 sq.m.
The area of the rectangle is 300 sq. meters.