please help with my chemistry thank you in advance :)

Question

a swimming pool, 10.0m by 4.0m, if filled with water to a depth of 3.0m at a temperature of 20.2 degree C. How much energy is required to raise the temperature of the water to 24.3 degrees C

energy= J

Answer 1

First, find the volume of water in the pool.

10.0 m x 4.0 m x 3.0 m = 120 m³

Next, convert this to liters, or mls.

120 m³ x 1x10⁶ ml/m³ = 120x10⁶ ml = 1.2x10⁸ ml

Now, if we assume that the density of the water is 1g/ml, we can estimate the mass of the water.

1.2x10⁸ ml x 1 g/ml = 1.2x10⁸ g

We can now use Q = mC∆T for find the energy needed to raise the temperature of this mass of water from 20.2ºC to 24.3ºC.

Q = heat = ?

m = mass = 1.2x10⁸ g

C = specific heat of water = 4.184 J/g/deg

∆T = change in temperature = 4.1ºC

Solving for Q: Q = (1.2x10⁸ g)(4.184 J/g/deg)(4.1 deg) = 2.059x10⁹ J = 2.1x10⁹ J = 2.110⁶ kJ = 2.1x10³ MJ