chemistry homework :(

Question

a balloon is filled to a volume of 6.65x10^2 mL at a temperature of 23.0°C. The balloon is then cooled at a constant pressure to a temperature of 1.36x10^2 K. What is the final volume of the balloon? Answer in mL

Answer 1

Constant pressure = Charles Law

V1/T1 = V2/T2

V1 = 665 ml

T1 = 23 + 273 = 296K

V2 = ?

T2 = 136K

V2 = (665 ml)(136K)/296K = 306 ml (to 3 significant figures)

Answer 2

Breaking down this problem, I see it asking what happens when you cool 665 ml of gas from 296^oK to 136^oK. So, since the temperature is cooling, we know the volume of the gas will shrink. How much? Simply multiply 665 ml X 136/296 = 305.54 ml.