J.R. S. answered 06/27/19
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat energy = ?
m = mass = 154.0 g
C = specific heat = 0.24 J/g/deg
∆T = change in temperature = 292 - 268 = 24º
q = (154 g)(0.24 J/g/deg)(24 deg) = 887 J = 890 J (to 2 significant figures)
1.0 mole Ag x 107.9 g/mole = 107.9 g/mole x 0.24 J/g/deg = 25.9 J = 26 J/ºC/mol
q = mC∆T
q = 1.07 kJ = 1070 J
m = ?
C = 0.24 J/g/deg
∆T = 1.3 deg
m = q/C∆T = 1070 J/(0.24 J/g/deg)(1.3 deg)
m = 3429 g = 3430 g (to 3 significant figures)