J.R. S. answered 06/27/19
Ph.D. University Professor with 10+ years Tutoring Experience
4Fe(s) + 3O2(g)---> 2Fe2O3(s)
A. -1652 kJ/4 mol Fe x 4.20 mol Fe = - 1735 kJ
B. -1652 kJ/2 mol Fe2O3 x 1 mol Fe2O3 = -826 kJ
C. 1.60 g Fe x 1 mol Fe/55.85 g x -1652 kJ/4 mol = -11.8 kJ
D. 10.5 g Fe x 1 mol Fe/55.85 g = 0.188 moles Fe
1.90 g O2 x 1 mol/32 g = 0.0594 moles O2
O2 is limiting as the mole ratio in balanced eq. is 3:4 for O2:Fe
0.0594 moles O2 x -1652 kJ/3 mol O2 = -32.7 kJ