chemistry homework:))

Question

a balloon is filled to a volume of 6.65x10^2 mL at a temperature of 23.0°C. The balloon is then cooled at a constant pressure to a temperature of 1.36x10^2 K. What is the final volume of the balloon? Answer in mL

Answer 1

At constant pressure, we are dealing with Charles Law:

V1/T1 = V2/T2

V1 = 6.65x10² ml

T1 = 23.0ºC + 273 = 296K

V2 = ?

T2 = 1.36x10²K

V2 = V1T2/T1 = (6.65x10² ml)(1.36x10²K)/296

V2 = 3.055x10² ml = 306 ml