
Sam Z. answered 06/24/19
Math/Science Tutor
4/3*r^3pi is the cum/measure.
4/3*3^3pi=113.097cu/in
*70
=7916.81cu/in
Emita P.
asked 06/24/19Keiko's company makes solid spherical metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6in
.If Keiko must make 70
of these balls, how much aluminum will she need?
If necessary, refer to the list of geometry formulas.
Sam Z. answered 06/24/19
Math/Science Tutor
4/3*r^3pi is the cum/measure.
4/3*3^3pi=113.097cu/in
*70
=7916.81cu/in
Ron G. answered 06/24/19
Multiple levels Math, Science, Writing
ΠA ball with a 6-inch diameter has a radius (call it r) of 3.
Each ball has a volume of (4/3) Π r3. Substitute 3 for r and get a volume of 36Π Π in3.
Keiko needs enough aluminum for 70 balls. 70 * 36 Π = 2520 Π in3.
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