Kurt C. answered 06/25/19
Looking up the Z value of 1.9 in a Z-score table shows .9713.
This means the probability is .9713 or 97.13%.
Marcella A.
asked 06/23/19Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C.
A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than 1.9°C.
P(Z<1.9)=
Kurt C. answered 06/25/19
Looking up the Z value of 1.9 in a Z-score table shows .9713.
This means the probability is .9713 or 97.13%.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.