J.R. S. answered 06/22/19
Ph.D. University Professor with 10+ years Tutoring Experience
For this titration the balanced equation is HCl + NaOH ==> NaCl + H2O
moles NaOH needed to neutralize the HCl = 40.05 ml x 1L/1000 ml x 0.250 mol/L = 0.0100 moles NaOH
moles HCl present = 0.0100 moles HCl
Concentration of HCl = 0.0100 moles/0.0500 L = 0.200 M (to 3 significant figures)