Chemistry homework of PV=NRT

Question

Complete the following:

P V n T

a) 7.74x10^3 Pa 12.8mL ? Mol 25° C

b) ? atm 43.0mL 0.442Mol 223° K

c) 413torr ? L 4.4x10^-2 mol 331° C

d) 745mmHg 10.8L 0.401mol ?° C

Answer 1

I'll do a couple and you should do the rest. See also the answer to your previous question.

a) PV = nRT

convert Pa to kPa: 7.74x10³ Pa x 1 kPa/10³ Pa) = 7.74 kPa

convert ml to L: 12.8 ml x 1 L/1000 ml = 0.0128 L

convert ºC to K: 25.0 + 273 = 298K

n = PV/RT = (7.74 kPa)(0.0128 L)/(0.0821 L atm/Kmol)(298K) = 0.00405 moles

b) PV = nRT

convert ml to L: 43.0 ml x 1 L/1000 ml = 0.0430 L

P = nRT/V = (0.442 mol)(0.0821 Latm/Kmol)(223K)/0.0430 L = 188 atm

c) PV = nRT

convert 413 torr to atm: 413 torr x 1 atm/760 torr = 0.543 atm

convert T to K: 331ºC + 273 = 604K

V = nRT/P

plug in values and solve for V in liters

d) PV = nRT

convert mm Hg to atm: 745 mm Hg x 1 atm/760 mm Hg = 0.980 atm

solve for T: T = PV/nR

plug in values and solve for T in K, then subtract 273 to get temperature in ºC