Chem homework of PV=nRT

Question

Complete the following :

P(atm). V(L). N(mol). T

1) 5.52 ? 2.00 155° C

2) 0.300 2.21 ? 155° K

3) 4.47 25.0 2.06 ? ° C

4) ? 2.25 10.5 61° C

Answer 1

P = 5.52 atm; n = 2.00 mol; T = 155ºC + 273 = 428K; V = ?

PV = nRT

V = nRT/P = (2.00 mol)(0.0821 Latm/Kmol)(428K)/5.52 atm = 12.7 L

P = 0.300 atm; V = 2.21 L; n = ? T = 155ºC + 273 = 428K

PV = nRT

n = PV/RT = (0.300 atm)(2.21 L)/(0.0821 Latm/Kmol)(428K) = 0.0189 moles

P = 4.47 atm; V = 25.0 L; n = 2.06 moles; T = ?

PV = nRT

T = PV/nR = (4.47 atm)(25.0 L)/(0.0821 Latm/Kmol)(2.06 moles) = 661K = 661-273 = 388ºC

P = ?; V = 2.25 L; n = 10.5 moles; T = 61ºC + 273 = 334K

PV = nRT

P = nRT/V plug in the numbers and solve as done above.