What is the maximum Mass that can be produce from a mixture of 2.00*10³g N2 and 8.00*10⁴g H2

Question

How can will find the maximum Mass of ammonia

Answer 1

Write the balanced equation:

N₂ + 3H₂ ==> 2NH₃

Next find the limiting reactant:

moles N₂ present = 2000 g x 1 mole/28 g = 71.4 moles N₂

moles H₂ present = 80,000 g x 1 mole/2 g = 40,000 moles H₂

Based on the mol ratio of H₂ to N₂ of 3:1, the limiting reactant is N₂

max. mass NH₃ = 71.4 mol N₂ x 2 mol NH₃/mol N₂ x 17 g/mol NH₃ = 2429 g NH₃ = 2430 g NH₃ (to 3 sig. figs.)