How do I find the point where the tangent, y=8x-16 meets the curve y=x²?

Answer 1

y = x^2 = 8x - 16

x^2 - 8x + 16 = 0

x = [8 +or- sqrt( 64 - 4*1*16)]/2

= [ 8 +or- sqrt( 64 - 64)]/2

= 8 / 2

= 4

Plug x=4 into both function to get y=16

(4,16)