Patrick B. answered 06/18/19
Math and computer tutor/teacher
Probability of 2 or more successes in 6 trials
That is the same as 1 minus Probability of zero successes minus 1 success
Prob(X>=2) =
1 - Prob(X<2) =
1 - [ Prob(x=0) + Prob(X=1) ] =
1 - Prob(X=0) - Prob(X=1)
p=0.256
k=0,1
N=6
Prob(X=0) =
(6 choose 0) * 0.256^0 * 0.744^6 =
1 * 1 * 0.744^6 = 0.169604594650054656
Prob(X=1) =
(6 choose 1) * 0.256^1 * 0.744^5 =
6 * 0.256 * 0.227963164852224 = 0.350151421213016064
THe probability is 0.48024398413692928 or just over 48%