Mathew M. answered 06/20/19
BSEE in Electrical Engineering and 34 years engineering experience
I would solve it this way:
x = regular price
x - .34x = 627
x(1-.34) = 627
x = 627/(1-.34)
x = 950
The suit's regular price is $950
Mathew M. answered 06/20/19
BSEE in Electrical Engineering and 34 years engineering experience
I would solve it this way:
x = regular price
x - .34x = 627
x(1-.34) = 627
x = 627/(1-.34)
x = 950
The suit's regular price is $950
Lisa M. answered 06/19/19
Middle School through College Level Math, PSAT/SAT/ACT + More!
I like to use proportions for these types of questions. If you keep in mind the concept of "part over whole" you can easily set it up correctly. You also need to keep in mind that if there is a discount, you need to subtract it from 1 (if in decimal form) or 100 (if in percent form) to get the "part" that you are paying.
66/100 = 627/x
x = $950
MathMadeEZ
$950.00
Since the discount is 34% that means that the sale price is
(100 - 34) of the regular price or 66%
So the regular price is sale price/.66
Let R = Regular Price
627 is the Sale Price
Sale Price/Regular Price = Percent/100
627/R = 66/100
Cross Multiply to solve for R
627 = 66/100 *R
627 * 100/66 = R
R = 950
Checking
(950 - 627) * 100/(950) = 34% the discount.
I hope you find this useful if you have questions send me a message.
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