J.R. S. answered 06/15/19
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Cr(OH)3 + NaOH ==> NaCrO2 + 2H2O
83.3 g Cr(OH)3 x 1 mole/103 g x 1 mole NaCrO2/mole Cr(OH)3 x 107 g/mole = 86.5 g (3 sig. figs.)