
Patrick B. answered 06/15/19
Math and computer tutor/teacher
a) 50% * 100% <--- 100% of getting neither defective from the 50% batch
+ 35% * 9/10*8/9 <--- probability of getting no defectives from the 35% batch containing 1 defective
+ 15% * 8/10*7/9 <--- probability of getting no defectives from the 15% batch containing 2 defectives
b) 50% * 0%
+ 35% * 2/10 + 15% * 2/10 * 8/9
c) 50% * 0% + 35% * 0% + 15% * 2/10*1/9