Random Variable Probability Russian Roulette?

Question

I am very confused on this one. Any help in how to solve it and what probability rule to use would be appreciated. Consider the situation in which a person played Russian roulette (one bullet, 6 chambers) until the bullet fires. Let X be the random variable that represents the number of shots until the game ends. Clearly, this number includes all shots, including the one in which bullet fires. a) What values can X take? b) Find the probability for each of the following: X = 1, 3, 5, 7, 9

Answer 1

Use geometric probability distribution to solve this.

P(X=x)= (1/6)(5/6)^(x-1)