For the following reaction, if O2 is used up at a rate of 1.45Mhr, what is the rate of formation of NO? 4NH3+5O2→4NO+6H2O

Answer 1

4NH₃ + 5O₂ ==> 4NO + 6H₂O

The mole ratio of NO to O₂ is 4:5, so every time 5 moles of O2 is used up, you will form 4 moles of NO. To find the rate of formation of NO under these conditions, it will be as follows:

1.45 O₂ x 4 NO/5O₂ = 1.16 Mhr^-1

(Note: the rate is not Mhr but M/hr, or Mhr^-1)