In circle k(o)
R an inscribed angle in Arc FPQ
Arc FPQ = mFP + mPQ
The measure of an inscribed angle in an arc is half the measure of the intercepted arc.
m∠R =(12x + 1) = 1/2(FPQ) = 1/2((11x + 7) + 60)
So
12x + 1 = 1/2(11x + 7 + 60)
First solve this for x
Then plug x into the given equation for FP
You can also complete all the substitutions and use that information to check your work.
I believe this question has been worked already here did you enter it twice? Anyway I do hope you find this useful, if you have any questions, please send me a message.