In a neutralization reaction 54.7 mL of 0.375 M sulfuric acid is required to completely react with 35.1 mL of sodium hydroxide. Determine the molarity of the sodium hydroxide needed

Question

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Answer 1

2NaOH + H₂SO₄ ==> 2H₂O + Na₂SO₄ ... balanced equation

0.0547 L x 0.375 mol/L = 0.0205 moles H₂SO₄ used

moles NaOH present = 0.0205 moles H₂SO₄ x 2 moles NaOH/mol H₂SO₄ = 0.0410 moles NaOH

molarity of the NaOH = moles/liter = 0.0410 moles/0.0351 L = 1.17 M