J.R. S. answered 05/31/19
Ph.D. University Professor with 10+ years Tutoring Experience
(a). 0.0ºC + 273.15 = 273.15K
(b). P1V1/T1 = P2V2/T2
(c). P1V1 = P2V2 at constant temperature. (1 atm)(22.4L) = (1.50 atm)(V2) and V2 = 14.9 L
(d). V1/T1 = V2/T2 at constant volume. (22.4 L)/(273K) = (V2)/(373K) ande V2 = 30.6 L