1). P(780 <= x <= 806) =P( z < (806-791)/8 ) - P( z < (780-791)/8 ). Now you can use z table to find the probability;
2) 9% = P( Z < (x - 791)/8). Now get the associated Z value for the 9% on normal distribution then use algebra to solve x.
Katie F.
asked 05/28/191.) A particular fruit's weights are normally distributed, with a mean of 791 grams and a standard deviation of 8 grams.
If you pick one fruit at random, what is the probability that it will weigh between 780 grams and 806 grams?
2.) A manufacturer knows that their items have a normally distributed lifespan, with a mean of 2.3 years, and standard deviation of 0.7 years.
The 9% of items with the shortest lifespan will last less than how many years?
3.) In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 54.3 inches, and standard deviation of 8.1 inches.
What is the probability that the height of a randomly chosen child is between 37.35 and 63.15 inches? Do not round until you get your your final answer, and then round to 3 decimal places.
1). P(780 <= x <= 806) =P( z < (806-791)/8 ) - P( z < (780-791)/8 ). Now you can use z table to find the probability;
2) 9% = P( Z < (x - 791)/8). Now get the associated Z value for the 9% on normal distribution then use algebra to solve x.
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