How many grams of calcium hydroxide are needed to completely react with 25.0 mL of 0.100 M nitric acid?

Question

please help i dont understand

Answer 1

Write the balanced equation:

Ca(OH)₂ + 2HNO₃ ==> Ca(NO₃)₂ + 2H₂O (base + acid = neutralization reaction)

Find the moles of nitric acid present:

25.0 ml x 1 L/1000 ml x 0.100 moles/L = 0.0025 moles HNO₃

Find moles calcium hydroxide needed to react with 0.0025 moles of HNO₃:

0.0025 moles HNO₃ x 1 mole Ca(OH)₂/2 moles HNO₃ = 0.00125 moles Ca(OH)₂

Convert moles of Ca(OH)_{2 t}o grams of Ca(OH)₂:

0.00125 moles Ca(OH)₂ x 74.09 g/mole = 0.0926 g (to 3 significant figures)