Matthew C. answered • 05/27/19
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Bachelor's of Science in Chemistry
The ionization of acetic acid is:
CH3COOH ⇌ CH3COO- + H+
Ka therefore is:
Ka = [CH3COO-][H+]/[CH3COOH]
Kehlani F.
asked • 05/27/19Ka expression for an ionization
What would be the ka expression for the ionization of acetic acid (a weak acid).
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