J.R. S. answered 05/23/19
Ph.D. University Professor with 10+ years Tutoring Experience
Graham's Law of Effusion:
rate gas 1/rate gas 2 = √MW gas 2/√MW gas 1
gas 1 = CO2 (MW = 44)
gas 2 = He (MW = 4)
410/x = √4/√44
410/x = 0.30
x = 1367 m/s
A helium balloon and a balloon filled with carbon dioxide are punctured with holes of the same size. At what speed does the helium effuse if the carbon dioxide effuses at a speed of 410. m/s?
J.R. S. answered 05/23/19
Ph.D. University Professor with 10+ years Tutoring Experience
Graham's Law of Effusion:
rate gas 1/rate gas 2 = √MW gas 2/√MW gas 1
gas 1 = CO2 (MW = 44)
gas 2 = He (MW = 4)
410/x = √4/√44
410/x = 0.30
x = 1367 m/s
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