J.R. S. answered 05/23/19
Ph.D. University Professor with 10+ years Tutoring Experience
If you assume you have 100 g of the compound, then you have 65 g gold (Au) and 35 g chlorine (Cl)
65 g Au x 1 mole/196.97 g = 0.32999 moles Au
35 g Cl x 1 mole/35.45 g = 0.9873 moles Cl
Dividing both by 0.32999, we obtain
1 mole Au
3 moles Cl
Formula of the compound = AuCl3 = gold(III) chloride
The other form of gold chloride would be AuCl = gold(I) chloride