Tom K. answered 05/27/19
Knowledgeable and Friendly Math and Statistics Tutor
For fair dice, P(7) = 1/6, P(11) = 1/18, and P(other) = 7/9
Then, with 360 rolls, the expected number of 7s, 11s, and others is 60, 20, and 280.
Thus, the Chi-square statistic is (74-60)^2/60 + (24-20)/^2/20 + (262-280)^2/280 =
196/60 + 16/20 + 324/280 = OR 5 47/210.
The critical statistic for chi-square p = .05 with 2 degrees of freedom is, from Excel, =CHISQ.INV.RT(0.05,2) = 5.99
5.22 < 5.99, so we fail to reject the null hypothesis that the dice are fair.
Note that we need to construct this test before the rolls, not after; otherwise, the test is not appropriate.