Stoichiometry question

Question

Calculate the mass of precipitate formed when 17.40g of aqueous silver nitrate is reacted with excess potassium chloride solution at SATP

Answer 1

AgNO₃(aq) + KCl(aq) ==> AgCl(s) + KNO₃(aq) ... balanced equation

moles AgNO₃ used = 17.40 g x 1 mole/169.87 g = 0.1024 moles

Since there is xs KCl, all the AgNO₃ will be converted to AgCl

0.1024 moles AgCl x 143.32g/mole = 14.68 g AgCl