A copper coin with a mass of 6.30 grams changes temperature in the sunshine from 20.0°C to 32.0°C. How much energy is transferred?

Question

The amount of energy transferred to the coin is  how many joules.

Answer 1

q = mC∆T

q = heat = ?

m = mass = 6.30 g

C = specific heat = 0.385 J/g/deg

∆T = change in temperature = 32-20 = 12º

q = ((6.30 g)(0.385 J/g/deg)(12 deg) = 29.1 J (to 3 significant figures)

Answer 2

Q = mc ΔT

where Q is the heat transfer, m is the mass of the coin, c is the specific heat capacity of copper, and ΔT is the change in temperature.

m = 6.30 g = 6.30 X 10^-3 kg.

c = 385 J/kg·°C, the specific hear of copper that I looked up on my phone

ΔT = 32°C - 20°C = 12°C, the temperature change.

Then,

Q = (6.30 X 10^-3 kg)(385 J/kg·°C)(12°C) = 29.1 Joules