J.R. S. answered 05/18/19
Ph.D. University Professor with 10+ years Tutoring Experience
6CO2(g) + 6H2O ==> C6H12O6 + 6O2
16.7 kg H2O x 1000g/kg x 1 mol/18 g = 928 mol H2O
928 mol water x 6 mol O2 / 6 mol water = 928 mol O2
The volume of O2 depends on the temperature and pressure. If the system is at STP, then 1 mol of gas = 22.4 liter.
Here we have 928 Mol x 22.4 L/ Mol = 20,787 L H2O