How do you solve sin4x=√3/2

Question

Solve for all solutions. Math Homework

Answer 1

Let 4x=u

Then sinu=√3/2

so sin^-1√3/2=u

u ={π/3+2πn, + 2π/3+2πn}

Substituting back u=4x gives

4x ={π/3+2πn, 2π/3+2πn}

(Dividing both sides by 4)

x = {π/12+πn/2 ,2π/12+πn/2}={π/12,7π/12,13π/12,19π/12,π/6,4π/6,7π/6,10π/6} on the interval [0,2π)

Answer 2

u = 4x

sin u = √3 / 2

u = 60°

4x = 60°

Can you solve for x and answer?