J.R. S. answered 05/15/19
Ph.D. University Professor with 10+ years Tutoring Experience
a). ∆ [H2O2]/t = 0.500 M/2.16x104 s = 2.31x10-5 M/s
b). ∆ [O2]/t = 1/2 ∆ [H2O2]/t = 1/2 * 2.3x10-5 M/s = 1.16x10-5 M/s
Sara M.
asked 05/15/19At 40 Celsius, H2O2 (aq) will decompose according to the following reaction:
2H2O2 (aq)→2H2O (l) + O2 (g)
The following data were collected for the concentration of H2O2 at various times.
Time(s) [H2O2](mol/L)
0 1.000
2.16 × 104 0.500
4.32 × 104 0.250
a.) Calculate the average rate of decomposition of H2O2 between 0 and 2.16 × 104 s.
b.) Use the rate to calculate the average rate of production of oxygen gas over the same time period.
J.R. S. answered 05/15/19
Ph.D. University Professor with 10+ years Tutoring Experience
a). ∆ [H2O2]/t = 0.500 M/2.16x104 s = 2.31x10-5 M/s
b). ∆ [O2]/t = 1/2 ∆ [H2O2]/t = 1/2 * 2.3x10-5 M/s = 1.16x10-5 M/s
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