Ellen E. answered 05/15/19
Chemistry Tutor - High School, AP, College
Here's what you gotta know about Reduction Potentials.
The LARGER the "Reduction Potential" the more likely it is that that reduction reaction will happen; i.e., the more likely that substance will be reduced.; i.e, the more likely that substance will be the one to accept the electrons (as opposed to being the substance that gives up electrons/be oxidized).
So in these questions....
a) we want to know if H+ will accept the electrons from Cu (s) which will be oxidized to Cu2+.
The reduction potential of Cu2+ to Cu(s) is +0.34
The reduction potential of H+ to H2 is 0
Which of these has the LARGER reduction potential?
Cu2+
Therefore Cu2+ is more likely to be reduced than H+.
So ,Cu 2+ will go to Cu(s) while H2 goes to H+ BUT NOT THE OTHER WAY AROUND. [ Cu(s) does not go to Cu2+ while H+ goes to H2, which means that Cu(s) cannot be oxidized by H+)
No, H+ cannot oxidize Cu(s)
b) Reduction potential of Ag+ to Ag (s) is 0.8
Reduction potential of H+ to H2 is 0
Reduction potential of Ag+ is larger than the reduction potential of H+.
Therefore, Ag + to Ag (s) is more likely to happen than H+ to H2.
That is, Ag+ will go to Ag (s) while H2 goes to H+ BUT NOT THE OTHER WAY AROUND. [Ag (s) will not be oxidized to Ag+ while H+ is reduced to H2)
So, Yes, H2 can reduce Ag+ to Ag (s)