
Mark M. answered 12/09/14
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Mathematics Teacher - NCLB Highly Qualified
First isolate the absolute value. Divide both sides by -4. Multiplying or dividing and inequality by a negative reverses the order.
-4 |x + 3| ≥ -20
|x + 3| ≤ 5
Absolute values are solved twice. Once assuming the number (here x + 5) is positive and then assuming it is negative.
I. |x + 3| ≤ 5 positive
x + 3 ≤ 5
x ≤ 3
II. |x + 3| ≤ 5 negative
-(x + 3) ≤ 5
-x - 3 ≤ 5
-x ≤ 8
x ≥ -8 multiplied by a negative, order changes
Closed dot on -8 line extending to closed dot on 3.