DEL R. answered 05/14/19
You could use the geometric probability distribution or just apply the multiplication rule for independent events.
Let T = Event of rolling a 2, Tc = Event of not rolling a 2.
P(T)=1/6 and P( Tc =5/6.
By independence, the probability the the first two is rolled after first 6 rolls:
P(Tc) * P(Tc) * P(Tc) * P(Tc) * P(Tc) * P(Tc) * P(T) [first 6 rolls, are not 2, then the 7th roll is a 2)
= (5/6)6 * (1/6)
= 15625 / 279936
~ 0.0558