Calculate molarity- acids and bases

Question

Calculate the molarity of 30.00 mL of HCl titrated with 17.45 mL of 3.500 M KOH

Answer 1

HCl + NaOH ==> NaCl + H2O ... balanced equation

moles NaOH used = 0.01745 L x 3.5 mol/L = 0.061075 moles NaOH

moles HCl present = 0.061075 moles NaOH x 1 mol HCl/mol NaOH = 0.061075 moles HCl

molarity HCl = 0.061075 moles/0.03000 L = 2.036 M (to 4 significant figures)