J.R. S. answered 05/11/19
Ph.D. University Professor with 10+ years Tutoring Experience
1.0 hr x 60 min/hr x 60 sec/min = 3600 sec
15 A = 15 C/sec
15 C/sec x 3600 sec = 54,000 C
54,000 C x 1 mole e- /96485C = 0.5597 moles electrons
0.5597 mol electrons x 1 mol Co/2 mol e- x 58.9 g/mol = 16.5 g =
17 g of cobalt