J.R. S. answered 05/11/19
Ph.D. University Professor with 10+ years Tutoring Experience
Mn+2 +2e− →Mn ε°=−1.18 V (anode) x 3
Fe+3 + 3e− →Fe ε°=−0.036 V (cathode) x 2
2Fe3+ + 3Mn ==> 2Fe + 3Mn2+
E = -.036 - (-1.18) = +0.82 V
It would be spontaneous since voltage is positive.