Number of units damaged by inductor in 10 min = rate x time = 1200 * (10/60 hr) = 200.
PS rate is 20 /hr
Number of PS hr needed = Quantity /fix-rate = 200/20 = 10 hr.
Eugenie P.
asked 05/11/19If an inductor makes mistake for 10min, how many ps hours will it take to fix the damage.(assuming ps can process around 20 orders an hour and each inductor is doing 1200uph)
Number of units damaged by inductor in 10 min = rate x time = 1200 * (10/60 hr) = 200.
PS rate is 20 /hr
Number of PS hr needed = Quantity /fix-rate = 200/20 = 10 hr.
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