Name the product(s) that are produced and classify the reaction?

Question

hydrogen bromide + pent-2-ene →

type of reaction: (addition, substitution, elimination?)

Answer 1

The reaction is addition, however, both hydrogen (H) and bromide (Br^-) add to the double bond. The final product formed is an alkyl halide. For this reaction, you would form a mixture of 2 alkyl halide products, namely, 2-bromopentane and 3-bromopentane, respectively. The reaction can be written as:

CH₃CH=CHCH₂CH₃ + HBr → CH₃–CH(Br)–CH₂CH₂CH₃ + CH₃CH₂–CH(Br)–CH₂CH₃

Answer 2

This video may help!

Answer 3

You are adding hydrogen across a double bond: addition

Product would be pentane