J.R. S. answered 05/09/19
Ph.D. University Professor with 10+ years Tutoring Experience
Use dimensional analysis:
11 g Na x 1 mol Na/23 g Na x 2 mol Na2O/4 mol Na x 62 g Na2O/mol Na2O = 14.8 g Na2O = 15 g Na2O
Katelyn M.
asked 05/09/19J.R. S. answered 05/09/19
Ph.D. University Professor with 10+ years Tutoring Experience
Use dimensional analysis:
11 g Na x 1 mol Na/23 g Na x 2 mol Na2O/4 mol Na x 62 g Na2O/mol Na2O = 14.8 g Na2O = 15 g Na2O
Keith W. answered 05/09/19
Working Mathematician with Expertise in Applied and Discrete Fields
11g Na* (1mol Na)/(23g Na) *(2 mol Na_2 O)/(4 mol Na) * (62 g Na_2 O)/(1mol Na_2 O)=14.82 g Na_2 O
molecule weights are taken from the periodic table.
Start with grams of Na then convert to moles then multiply by the mole to mole ration of Na to Na2O and then convert moles of Na2O to grams.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.