Determine Cell Potential

Question

Pt(s)∣∣Fe+2(aq),Fe+3(aq)∣∣|Ag+(aq)|Ag(s)

Determine the cell potential for this galvanic cell.

Answer 1

Since by convention, the cathode is written on the right and anode is written on the left, we have...

Fe²⁺(aq) ==> Fe³⁺(aq) + e- oxidation (anode)

Ag⁺(aq) + e- ==> Ag(s) reduction (cathode)

You then need to look up the standard reduction potentials, which I find to be

Fe³⁺ + e- ==> Fe²⁺ +0.77V

Ag⁺ +e- ==> Ag +0.7996V

Eº_cell = 0.7996 - 0.77 = 0.0296V