J.R. S. answered 05/07/19
Ph.D. University Professor with 10+ years Tutoring Experience
∑products - ∑reactants = ∆Sreaction
∑products = 2*28 + 3*189 = 623 J/K mol
∑reactants = 51 + 3*131 = 444 J/K mol
∆S = 623 - 444 = 179 J/K mol
Sara M.
asked 05/07/19Calculate ∆So for the reduction of aluminum oxide by hydrogen gas:
Al2O3 (s) + 3H2 (g) →2Al (s) + 3H2O (g)
using the following standard entropy values:
Substance So (J/K mol)
Al2O3 (s) 51
H2 (g) 131
Al (s) 28
H2O (g) 189
J.R. S. answered 05/07/19
Ph.D. University Professor with 10+ years Tutoring Experience
∑products - ∑reactants = ∆Sreaction
∑products = 2*28 + 3*189 = 623 J/K mol
∑reactants = 51 + 3*131 = 444 J/K mol
∆S = 623 - 444 = 179 J/K mol
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