solve the equation -5cos^2x-sinx+2=0 on the interval [0 degrees, 360 degrees)

Question

-5cos(squared)x-sinx+2=0

Answer 1

-5cos² x - sin x + 2 = 90

cos² x= 1 - sin² x

-5(1 - sin² x) - sin x + 2 = 0

-5 + 5sin² x - sin x + 2 = 0

5sin² - sin x - 3 = 0

This has irrational roots.